Search by Image, Recursively, Transparent PNG, #1 by Sebastian Schmieg:

import re, subprocess, time

class GoogleSearchByImage :

GOOGLE_URL = “http://www.google.com”

GOOGLE_SBI_URL = “/searchbyimage?image_url=”

AGENT_ID = “Mozilla/5.0 (X11; Linux x86_64; rv:7.0.1) Gecko/20100101 Firefox/7.0.1”

MIN_SECONDS_BETWEEN_REQUESTS = 2

_myLastRequestTimestamp = 0

_myCurrentHtml = “”

def scrape(self, theReference) :
if time.time() – self._myLastRequestTimestamp < self.MIN_SECONDS_BETWEEN_REQUESTS : time.sleep(self.MIN_SECONDS_BETWEEN_REQUESTS - (time.time() - self._myLastRequestTimestamp)) return self.scrape(theReference) else : self._myCurrentHtml = self.getHtml(self.GOOGLE_URL + self.GOOGLE_SBI_URL + theReference) self._myLastRequestTimestamp = time.time() def getHtml(self, theUrl) : try : myHtml = subprocess.check_output(["curl", "-L", "-A", self.AGENT_ID, theUrl], stderr=subprocess.STDOUT) return myHtml except : print "Curl error. Will sleep for 10 seconds" time.sleep(10) return self.getHtml(theUrl) def getSimilarImages(self) : myPattern = re.compile("\" href\=\"\/imgres\?imgurl\=(.*?)(\&amp|\%3F)") myImages = myPattern.findall(self._myCurrentHtml) myImagesUrls = [] for myImage in myImages : myImagesUrls.append(myImage[0]) return myImagesUrls def getLinkToSimilarImagesPage(self) : myPattern = re.compile("\Visually similar images\<\/a\>“)
myPageUrl = myPattern.findall(self._myCurrentHtml)
myPageUrl = str(myPageUrl[0]).replace(“&”, “&”)
myPageUrl += “&biw=1600&bih=825” # always keep this
return self.GOOGLE_URL + myPageUrl